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Three identical cells each of e.m.f. 2 V and unknown internal resistances are connected in parallel. This combination is connected to a 5 Ω resistor. If the terminal voltage across the cell is 1.5 V, then internal resistance of each cell is
  • a)
    3 Ω
  • b)
    4 Ω
  • c)
    5 Ω
  • d)
    6 Ω
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Three identical cells each of e.m.f. 2 V and unknown internal resistan...
Given Data:
E.M.F of each cell (E) = 2 V
Terminal voltage across the cell (V) = 1.5 V
Resistance in the circuit (R) = 5 Ω

To find: Internal resistance of each cell

Formula used: V = E - Ir

Where,
V = Terminal voltage across the cell
E = E.M.F of each cell
I = Current flowing through the circuit
r = Internal resistance of each cell

Calculation:
Let the internal resistance of each cell be r.
The three cells are connected in parallel. So, the equivalent internal resistance of the combination of cells will be:
r' = r/3

Total current flowing through the circuit, I = V/R

Current flowing through each cell, I' = I/3

Using the formula, V = E - Ir, we get:
1.5 = 2 - I'r
1.5 = 2 - (I/3)r
1.5 = 2 - (1.5/5)r (R = 5 Ω)
1.5 = 2 - 0.3r
0.3r = 0.5
r = 5 Ω

Therefore, the internal resistance of each cell is 5 Ω.

Answer: Option (C) 5
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Community Answer
Three identical cells each of e.m.f. 2 V and unknown internal resistan...
For cell in parallel combinations E'= E, r'= r/n where n=3. I= E'/ R+r' => I= nE/ nR+r. and using V=IR find I, put value we get r=5.
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Three identical cells each of e.m.f. 2 V and unknown internal resistances are connected in parallel. This combination is connected to a 5 Ω resistor. If the terminal voltage across the cell is 1.5 V, then internal resistance of each cell isa)3 Ωb)4 Ωc)5 Ωd)6 ΩCorrect answer is option 'C'. Can you explain this answer?
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