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A current carrying closed loop in the form of a right angle isosceles triangle ABC, right angled at B, is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on AC is A) √2F B) -√2F C) -F D) F?
Most Upvoted Answer
A current carrying closed loop in the form of a right angle isosceles ...
Force on AB is zero ( f = i( lB) sin theta , here theta is zero) . Total mag field in the current carrying closed loop is zero . Fab+ Fbc + Fac = 0
Fac=- Fbc. so c option is right.
Community Answer
A current carrying closed loop in the form of a right angle isosceles ...
Explanation:

1. Introduction:
In this scenario, we have a current carrying closed loop in the form of a right angle isosceles triangle ABC, with the right angle at B. The loop is placed in a uniform magnetic field acting along AB. We need to determine the force on the arm AC.

2. Magnetic Force on a Current-Carrying Wire:
When a current-carrying wire is placed in a magnetic field, it experiences a force perpendicular to both the current direction and the magnetic field direction. This force can be calculated using the formula:

F = BIL

Where:
- F is the magnetic force on the wire,
- B is the magnetic field strength,
- I is the current flowing through the wire, and
- L is the length of the wire segment within the magnetic field.

3. Analyzing the Triangle:
Let's consider the triangle ABC and analyze the forces acting on its arms:

- Arm BC: The length of arm BC within the magnetic field is equal to the length of the hypotenuse of the triangle, which is √2 times the length of either of its legs. Therefore, the force on arm BC can be given as F = BIL, where L = √2L1 (L1 is the length of either leg). So, F = B√2IL1.

- Arm AC: The length of arm AC within the magnetic field is equal to one of the legs of the triangle, which is L1. Therefore, the force on arm AC can be given as F = BIL, where L = L1. So, F = BIL1.

4. Comparing the Forces:
Comparing the forces on arms BC and AC, we can see that the force on BC is √2 times larger than the force on AC. This is because the length of BC within the magnetic field is √2 times larger than the length of AC within the magnetic field.

Therefore, the force on AC is given by F and the force on BC is √2F.

5. Conclusion:
Based on the analysis above, the correct answer is A) √2F. The force on the arm AC is √2 times smaller than the force on the arm BC.
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A current carrying closed loop in the form of a right angle isosceles triangle ABC, right angled at B, is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on AC is A) √2F B) -√2F C) -F D) F?
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A current carrying closed loop in the form of a right angle isosceles triangle ABC, right angled at B, is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on AC is A) √2F B) -√2F C) -F D) F? for NEET 2024 is part of NEET preparation. The Question and answers have been prepared according to the NEET exam syllabus. Information about A current carrying closed loop in the form of a right angle isosceles triangle ABC, right angled at B, is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on AC is A) √2F B) -√2F C) -F D) F? covers all topics & solutions for NEET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A current carrying closed loop in the form of a right angle isosceles triangle ABC, right angled at B, is placed in a uniform magnetic field acting along AB. If the magnetic force on the arm BC is F, the force on AC is A) √2F B) -√2F C) -F D) F?.
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