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A uniform silver wire has a resistivity of 1.54 x 10-8 Clm at room temperature and there are 5.8 x 1028 conduction electrons per m3. If an electric field of 1 volt cm is applied along the wire, the relaxation time of electron will be
  • a)
    3.97x10-14 s
  • b)
    3.97x10-15 s
  • c)
    3.97x10-13 s
  • d)
    3.97x10-16 s
Correct answer is option 'A'. Can you explain this answer?
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A uniform silver wire has a resistivity of 1.54 x 10-8Clm at room temp...
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Relaxation time τ is given by
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A uniform silver wire has a resistivity of 1.54 x 10-8Clm at room temp...
Given data:
- Resistivity of silver wire = 1.54 x 10^-8 Ωm
- Number of conduction electrons per m^3 = 5.8 x 10^28 electrons/m^3
- Electric field applied = 1 V/cm

To find: Relaxation time of electron

Formula used:
- Resistivity (ρ) = (m/ne^2)τ
where m = mass of electron, n = number of electrons per unit volume, e = charge of electron, and τ = relaxation time
- Electric current density (J) = nev
where J = current density, n = number of electrons per unit volume, e = charge of electron, and v = drift velocity
- Drift velocity (v) = (eEτ)/m
where E = electric field strength

Calculation:
- Mass of electron (m) = 9.1 x 10^-31 kg
- Charge of electron (e) = 1.6 x 10^-19 C
- Electric field strength (E) = 1 V/cm = 100 V/m
- Number of electrons per unit volume (n) = 5.8 x 10^28 electrons/m^3
- Electric current density (J) = nev = ne(eEτ)/m
- Resistivity (ρ) = (m/ne^2)τ
=> τ = (m/ne^2)ρ
=> τ = (9.1 x 10^-31)/(5.8 x 10^28 x (1.6 x 10^-19)^2 x 1.54 x 10^-8)
=> τ = 3.97 x 10^-14 s

Therefore, the relaxation time of electron is 3.97 x 10^-14 s (Option A).
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A uniform silver wire has a resistivity of 1.54 x 10-8Clm at room temperature and there are 5.8 x 1028conduction electrons per m3. If an electric field of 1 volt cm is applied along the wire, the relaxation time of electron will bea)3.97x10-14sb)3.97x10-15sc)3.97x10-13sd)3.97x10-16sCorrect answer is option 'A'. Can you explain this answer?
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