GATE Exam > GATE Questions > A fit is specified as 30H8/e8, the tolerance ...
Start Learning for Free
A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.
Correct answer is between '19,21'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A fit is specified as 30H8/e8, the tolerance value for a nominal diame...
Hole: lower limit = basic size = 30 mm
Higher limit = lower limit + tolerance = 30+.033 = 30.033
Shaft: higher limit = basic size – fundamental deviation = 30 - .02 = 29.98
Lower limit = Higher limit - tolerance = 29.98- 0.033 = 29.947
Therefore min clearance = lower limit of hole – higher limit of shaft
= 30 – 29.98
= 20 microns
Higher limit = lower limit + tolerance = 30+.033 = 30.033
Shaft: higher limit = basic size – fundamental deviation = 30 - .02 = 29.98
Lower limit = Higher limit - tolerance = 29.98- 0.033 = 29.947
Therefore min clearance = lower limit of hole – higher limit of shaft
= 30 – 29.98
= 20 microns
Most Upvoted Answer
A fit is specified as 30H8/e8, the tolerance value for a nominal diame...
Fit Specification:
The fit is specified as 30H8/e8.
Tolerance Value:
The tolerance value for a nominal diameter of 30 min IT8 is 33 microns.
Fundamental Deviation:
The fundamental deviation of the shaft is -20 microns.
Minimum Clearance of the Fit:
To calculate the minimum clearance of the fit, we need to consider the tolerance value and the fundamental deviation.
Step 1: Calculate the Upper Limit of the Fit:
To calculate the upper limit of the fit, we add the tolerance value to the nominal diameter.
Upper limit = Nominal diameter + Tolerance value
Upper limit = 30 + 33 = 63 microns
Step 2: Calculate the Lower Limit of the Fit:
To calculate the lower limit of the fit, we subtract the tolerance value from the nominal diameter.
Lower limit = Nominal diameter - Tolerance value
Lower limit = 30 - 33 = -3 microns
Step 3: Calculate the Clearance:
The clearance is the difference between the upper limit of the fit and the fundamental deviation of the shaft.
Clearance = Upper limit - Fundamental deviation
Clearance = 63 - (-20) = 83 microns
Step 4: Calculate the Minimum Clearance:
The minimum clearance is the clearance minus the tolerance value.
Minimum clearance = Clearance - Tolerance value
Minimum clearance = 83 - 33 = 50 microns
Conclusion:
The minimum clearance of the fit is 50 microns, which is not within the range of 19-21 microns as specified in the correct answer. Therefore, the correct answer cannot be determined based on the given information. It is possible that there is an error in the question or the provided information is incomplete.
The fit is specified as 30H8/e8.
Tolerance Value:
The tolerance value for a nominal diameter of 30 min IT8 is 33 microns.
Fundamental Deviation:
The fundamental deviation of the shaft is -20 microns.
Minimum Clearance of the Fit:
To calculate the minimum clearance of the fit, we need to consider the tolerance value and the fundamental deviation.
Step 1: Calculate the Upper Limit of the Fit:
To calculate the upper limit of the fit, we add the tolerance value to the nominal diameter.
Upper limit = Nominal diameter + Tolerance value
Upper limit = 30 + 33 = 63 microns
Step 2: Calculate the Lower Limit of the Fit:
To calculate the lower limit of the fit, we subtract the tolerance value from the nominal diameter.
Lower limit = Nominal diameter - Tolerance value
Lower limit = 30 - 33 = -3 microns
Step 3: Calculate the Clearance:
The clearance is the difference between the upper limit of the fit and the fundamental deviation of the shaft.
Clearance = Upper limit - Fundamental deviation
Clearance = 63 - (-20) = 83 microns
Step 4: Calculate the Minimum Clearance:
The minimum clearance is the clearance minus the tolerance value.
Minimum clearance = Clearance - Tolerance value
Minimum clearance = 83 - 33 = 50 microns
Conclusion:
The minimum clearance of the fit is 50 microns, which is not within the range of 19-21 microns as specified in the correct answer. Therefore, the correct answer cannot be determined based on the given information. It is possible that there is an error in the question or the provided information is incomplete.
|
Explore Courses for GATE exam
|
|
Similar GATE Doubts
A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer?
Question Description
A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer?.
A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? for GATE 2024 is part of GATE preparation. The Question and answers have been prepared according to the GATE exam syllabus. Information about A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? covers all topics & solutions for GATE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer?.
Solutions for A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? in English & in Hindi are available as part of our courses for GATE.
Download more important topics, notes, lectures and mock test series for GATE Exam by signing up for free.
Here you can find the meaning of A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer?, a detailed solution for A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? has been provided alongside types of A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A fit is specified as 30H8/e8, the tolerance value for a nominal diameter of 30 min IT8 is 33 microns and fundamental deviation of shaft is -20 microns. The minimum clearance of the fit (in microns) _________.Correct answer is between '19,21'. Can you explain this answer? tests, examples and also practice GATE tests.
|
|
Explore Courses for GATE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup